2n/n^2-3n

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Solution for 2n/n^2-3n equation: 


D( n )

n^2 = 0

n^2 = 0

n^2 = 0

1*n^2 = 0 // : 1

n^2 = 0

n = 0

n in (-oo:0) U (0:+oo)

(2*n)/(n^2)-(3*n) = 0

(2*n)/(n^2)-3*n = 0

2*n^-1-3*n^1 = 0

(2*n^0-3*n^2)/(n^1) = 0 // * n^2

n^1*(2*n^0-3*n^2) = 0

n^1

2-3*n^2 = 0

2-3*n^2 = 0

DELTA = 0^2-(-3*2*4)

DELTA = 24

DELTA > 0

n = (24^(1/2)+0)/(-3*2) or n = (0-24^(1/2))/(-3*2)

n = (-6^(1/2))/3 or n = (1*6^(1/2))/3

n in { (-6^(1/2))/3, (1*6^(1/2))/3} 

n in { (-6^(1/2))/3, (1*6^(1/2))/3 }

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